Mathematics
         
语言:中文    Language:English
                                Equations   
Fold
                                Unary equation
                                Multivariate equation
                                Math OP  
Unfold
                                Linear algebra      
Unfold
                                Derivative function
                                Function image
                                Hot issues
On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer
    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation 1/d+1/(d+50)+1/(d+100) = 0 .
    Question type: Equation
    Solution:Original question:
     1 ÷ d + 1 ÷ ( d + 50) + 1 ÷ ( d + 100) = 0
     Multiply both sides of the equation by: d
     1 + 1 ÷ ( d + 50) × d + 1 ÷ ( d + 100) × d = 0
     Multiply both sides of the equation by:( d + 50)
     1( d + 50) + 1 d + 1 ÷ ( d + 100) × d ( d + 50) = 0
    Remove a bracket on the left of the equation:
     1 d + 1 × 50 + 1 d + 1 ÷ ( d + 100) × d ( d + 50) = 0
    The equation is reduced to :
     1 d + 50 + 1 d + 1 ÷ ( d + 100) × d ( d + 50) = 0
    The equation is reduced to :
     2 d + 50 + 1 ÷ ( d + 100) × d ( d + 50) = 0
     Multiply both sides of the equation by:( d + 100)
     2 d ( d + 100) + 50( d + 100) + 1 d ( d + 50) = 0
    Remove a bracket on the left of the equation:
     2 d d + 2 d × 100 + 50( d + 100) + 1 d ( d + 50) = 0
    The equation is reduced to :
     2 d d + 200 d + 50( d + 100) + 1 d ( d + 50) = 0
    Remove a bracket on the left of the equation:
     2 d d + 200 d + 50 d + 50 × 100 + 1 d ( d + 50) = 0
    The equation is reduced to :
     2 d d + 200 d + 50 d + 5000 + 1 d ( d + 50) = 0
    The equation is reduced to :
     2 d d + 250 d + 5000 + 1 d ( d + 50) = 0
    Remove a bracket on the left of the equation:
     2 d d + 250 d + 5000 + 1 d d + 1 d × 50 = 0
    The equation is reduced to :
     2 d d + 250 d + 5000 + 1 d d + 50 d = 0
    The equation is reduced to :
     2 d d + 300 d + 5000 + 1 d d = 0

    The solution of the equation:
        d1≈-78.867513 , keep 6 decimal places
        d2≈-21.132487 , keep 6 decimal places
    
    There are 2 solution(s).


解程的详细方法请参阅:《方程的解法》



Your problem has not been solved here? Please go to the Hot Problems section!





  New addition:Lenders ToolBox module(Specific location:Math OP > Lenders ToolBox ),welcome。