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On line Solution of Monovariate Equation:
    Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
    It supports equations that contain mathematical functions.
    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer
    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation (x-1)*(x-4)*(x-5)+3(x-4)+6(x-1)+2(x-5) = 0 .
    Question type: Equation
    Solution:Original question:
     ( x 1)( x 4)( x 5) + 3( x 4) + 6( x 1) + 2( x 5) = 0
    Remove the bracket on the left of the equation:
     Left side of the equation = x ( x 4)( x 5)1( x 4)( x 5) + 3( x 4) + 6( x 1) + 2( x 5)
                                             = x x ( x 5) x × 4( x 5)1( x 4)( x 5) + 3( x 4) + 6
                                             = x x x x x × 5 x × 4( x 5)1( x 4)( x 5)
                                             = x x x x x × 5 x × 4 x + x × 4 × 5
                                             = x x x x x × 5 x × 4 x + x × 201
                                             = x x x x x × 5 x × 4 x + 20 x 1
                                             = x x x x x × 5 x × 4 x + 20 x 1
                                             = x x x x x × 5 x × 4 x + 20 x 1
                                             = x x x x x × 5 x × 4 x + 20 x 1
                                             = x x x x x × 5 x × 4 x + 25 x 1
                                             = x x x x x × 5 x × 4 x + 25 x 1
                                             = x x x x x × 5 x × 4 x + 25 x 1
                                             = x x x x x × 5 x × 4 x + 29 x 1
                                             = x x x x x × 5 x × 4 x + 29 x 1
                                             = x x x x x × 5 x × 4 x + 29 x 1
                                             = x x x x x × 5 x × 4 x + 32 x 1
                                             = x x x x x × 5 x × 4 x + 32 x 1
                                             = x x x x x × 5 x × 4 x + 32 x 1
                                             = x x x x x × 5 x × 4 x + 38 x 1
                                             = x x x x x × 5 x × 4 x + 38 x 1
                                             = x x x x x × 5 x × 4 x + 38 x 1
                                             = x x x x x × 5 x × 4 x + 40 x 1
    The equation is transformed into :
      x x x x x × 5 x × 4 x + 40 x 1 = 0

    
        x=2
    
    There are 1 solution(s).


解一元一次方程的详细方法请参阅:《一元一次方程的解法》



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