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    Current location:Equations > Monovariate Equation > The history of univariate equation calculation > Answer

    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation (0.001+y)/【(0.3-y)(0.01-y)】 = 3.2 .
    Question type: Equation
    Solution:Original question:
     (
1
1000
+ y ) ÷ ((
3
10
y )(
1
100
y )) =
16
5
     Multiply both sides of the equation by:((
3
10
y )(
1
100
y ))
     (
1
1000
+ y ) =
16
5
((
3
10
y )(
1
100
y ))
    Remove a bracket on the left of the equation::
     
1
1000
+ y =
16
5
((
3
10
y )(
1
100
y ))
    Remove a bracket on the right of the equation::
     
1
1000
+ y =
16
5
(
3
10
y )(
1
100
y )
    Remove a bracket on the right of the equation::
     
1
1000
+ y =
16
5
×
3
10
(
1
100
y )
16
5
y (
1
100
y )
    The equation is reduced to :
     
1
1000
+ y =
24
25
(
1
100
y )
16
5
y (
1
100
y )
    Remove a bracket on the right of the equation::
     
1
1000
+ y =
24
25
×
1
100
24
25
y
16
5
y (
1
100
y )
    The equation is reduced to :
     
1
1000
+ y =
6
625
24
25
y
16
5
y (
1
100
y )
    Remove a bracket on the right of the equation::
     
1
1000
+ y =
6
625
24
25
y
16
5
y ×
1
100
+
16
5
y y
    The equation is reduced to :
     
1
1000
+ y =
6
625
24
25
y
4
125
y +
16
5
y y
    The equation is reduced to :
     
1
1000
+ y =
6
625
124
125
y +
16
5
y y

    
        y≈0.618152 , keep 6 decimal places
    
    There are 1 solution(s).


解一元一次方程的详细方法请参阅:《一元一次方程的解法》



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