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On line Solution of Monovariate Equation：
Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
It supports equations that contain mathematical functions.
Input any unary equation directly, and then click the "Next" button to obtain the solution of the equation.
It supports equations that contain mathematical functions.
Current location：Equations > Monovariate Equation > The history of univariate equation calculation > Answer
Overview: 3 questions will be solved this time.Among them
☆3 equations
[ 1/3 Equation]
Work: Find the solution of equation x1-2x2+6x3 = 0 .
Question type: Equation
Solution:Original question:
The equation is transformed into :
The coefficient of the unknown number is reduced to 1 :
We obtained :
This is the solution of the equation.
[ 2/3 Equation]
Work: Find the solution of equation 2x3 = 0 .
Question type: Equation
Solution:Original question:
The equation is transformed into :
The coefficient of the unknown number is reduced to 1 :
We obtained :
This is the solution of the equation.
[ 3/3 Equation]
Work: Find the solution of equation -2x1+4x2+12x3 = 0 .
Question type: Equation
Solution:Original question:
The equation is transformed into :
The coefficient of the unknown number is reduced to 1 :
We obtained :
This is the solution of the equation.
☆3 equations
[ 1/3 Equation]
Work: Find the solution of equation x1-2x2+6x3 = 0 .
Question type: Equation
Solution:Original question:
| x | × | 1 | − | 2 | x | × | 2 | + | 6 | x | × | 3 | = | 0 |
| Left side of the equation = | x | × | 1 | − | 4 | x | + | 18 | x |
| = | 15 | x |
| 15 | x | = | 0 |
The coefficient of the unknown number is reduced to 1 :
| x | = | 0 | ÷ | 15 |
| = | 0 | × | 1 15 |
We obtained :
| x | = | 0 |
[ 2/3 Equation]
Work: Find the solution of equation 2x3 = 0 .
Question type: Equation
Solution:Original question:
| 2 | x | × | 3 | = | 0 |
| Left side of the equation = | 6 | x |
| 6 | x | = | 0 |
The coefficient of the unknown number is reduced to 1 :
| x | = | 0 | ÷ | 6 |
| = | 0 | × | 1 6 |
We obtained :
| x | = | 0 |
[ 3/3 Equation]
Work: Find the solution of equation -2x1+4x2+12x3 = 0 .
Question type: Equation
Solution:Original question:
| - | 2 | x | × | 1 | + | 4 | x | × | 2 | + | 12 | x | × | 3 | = | 0 |
| Left side of the equation = | - | 2 | x | + | 8 | x | + | 36 | x |
| = | 42 | x |
| 42 | x | = | 0 |
The coefficient of the unknown number is reduced to 1 :
| x | = | 0 | ÷ | 42 |
| = | 0 | × | 1 42 |
We obtained :
| x | = | 0 |