总述:本次共解1题。其中
☆算术计算1题
〖1/1算式〗
作业:求算式 (110-200)/(1+10%)+(50-90)/(1+10%)^2+(30-50)/(1+10%)^3 的值.
题型:数学计算
解:
(110-200)/(1+10%)+(50-90)/(1+10%)^2+(30-50)/(1+10%)^3
=-90/(1+10%)+(50-90)/(1+10%)^2+(30-50)/(1+10%)^3
=-90/1.1+(50-90)/(1+10%)^2+(30-50)/(1+10%)^3
=-90/1.1+(-40)/(1+10%)^2+(30-50)/(1+10%)^3
=-90/1.1+(-40)/1.1^2+(30-50)/(1+10%)^3
=-90/1.1+(-40)/1.1^2+(-20)/(1+10%)^3
=-90/1.1+(-40)/1.1^2+(-20)/1.1^3
=-90/1.1+(-40)/1.21+(-20)/1.1^3
=-90/1.1+(-40)/1.21+(-20)/1.331
=-81.818182+(-40)/1.21+(-20)/1.331
=-81.818182+(-33.057851)+(-20)/1.331
=-81.818182+-33.057851+(-15.026296)
=-114.876033+(-15.026296)
=-129.902329 答案:(110-200)/(1+10%)+(50-90)/(1+10%)^2+(30-50)/(1+10%)^3=-129.902329你的问题在这里没有得到解决?请到 热门难题 里面看看吧!