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It supports mathematical functions (including trigonometric functions).
Current location：Mathematical operation > History of Mathematical Computation > Answer
Overview: 1 questions will be solved this time.Among them
☆1 arithmetic calculations
[1/1 Formula]
Work: Calculate the value of equation (110-200)/(1+10%)+(50-90)/(1+10%)^2+(30-50)/(1+10%)^3 .
Question type: Mathematical calculation
Solution:
(110-200)/(1+10%)+(50-90)/(1+10%)^2+(30-50)/(1+10%)^3
=-90/(1+10%)+(50-90)/(1+10%)^2+(30-50)/(1+10%)^3
=-90/1.1+(50-90)/(1+10%)^2+(30-50)/(1+10%)^3
=-90/1.1+(-40)/(1+10%)^2+(30-50)/(1+10%)^3
=-90/1.1+(-40)/1.1^2+(30-50)/(1+10%)^3
=-90/1.1+(-40)/1.1^2+(-20)/(1+10%)^3
=-90/1.1+(-40)/1.1^2+(-20)/1.1^3
=-90/1.1+(-40)/1.21+(-20)/1.1^3
=-90/1.1+(-40)/1.21+(-20)/1.331
=-81.818182+(-40)/1.21+(-20)/1.331
=-81.818182+(-33.057851)+(-20)/1.331
=-81.818182+-33.057851+(-15.026296)
=-114.876033+(-15.026296)
=-129.902329
Answer:(110-200)/(1+10%)+(50-90)/(1+10%)^2+(30-50)/(1+10%)^3=-129.902329