总述:本次共解1题。其中
☆算术计算1题
〖1/1算式〗
作业:求算式 10/3-1-7^(log(3,2))+lg3-2+lg6+lg50 的值.
题型:数学计算
解:
10/3-1-7^(log(3,2))+lg3-2+lg6+lg50
=10/3-1-7^(0.63093)+lg3-2+lg6+lg50
=10/3-1-7^0.63093+lg3-2+lg6+lg50
=10/3-1-7^0.630930+0.477121-2+lg6+lg50
=10/3-1-7^0.630930+0.477121-2+0.778151+lg50
=10/3-1-7^0.630930+0.477121-2+0.778151+1.69897
=10/3-1-3.413482702020858+0.477121-2+0.778151+1.69897
=3.333333-1-3.413482702020858+0.477121-2+0.778151+1.69897
=2.333333-3.413482702020858+0.477121-2+0.778151+1.69897
=-1.08015+0.477121-2+0.778151+1.69897
=-0.603029-2+0.778151+1.69897
=-2.603029+0.778151+1.69897
=-1.824878+1.69897
=-0.125908 答案:10/3-1-7^(log(3,2))+lg3-2+lg6+lg50=-0.125908你的问题在这里没有得到解决?请到 热门难题 里面看看吧!