Mathematics
         
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    Current location:Mathematical operation > History of Mathematical Computation > Answer

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           ☆1 arithmetic calculations

[1/1 Formula]
    Work: Calculate the value of equation 10/3-1-7^(log(3,2))+lg3-2+lg6+lg50 .
    Question type: Mathematical calculation
    Solution:
          10/3-1-7^(log(3,2))+lg3-2+lg6+lg50
        =10/3-1-7^(0.63093)+lg3-2+lg6+lg50
        =10/3-1-7^0.63093+lg3-2+lg6+lg50
        =10/3-1-7^0.630930+0.477121-2+lg6+lg50
        =10/3-1-7^0.630930+0.477121-2+0.778151+lg50
        =10/3-1-7^0.630930+0.477121-2+0.778151+1.69897
        =10/3-1-3.413482702020858+0.477121-2+0.778151+1.69897
        =3.333333-1-3.413482702020858+0.477121-2+0.778151+1.69897
        =2.333333-3.413482702020858+0.477121-2+0.778151+1.69897
        =-1.08015+0.477121-2+0.778151+1.69897
        =-0.603029-2+0.778151+1.69897
        =-2.603029+0.778151+1.69897
        =-1.824878+1.69897
        =-0.125908

    Answer:10/3-1-7^(log(3,2))+lg3-2+lg6+lg50=-0.125908


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