总述:本次共解1题。其中
☆算术计算1题
〖1/1算式〗
作业:求算式 2/sqrt(3)*500*ln1-310+310*0.05^2/(0.1^2-0.05^2)*(0.1^2/0.05^2-1) 的值.
题型:数学计算
解:
2/sqrt(3)*500*ln1-310+310*0.05^2/(0.1^2-0.05^2)*(0.1^2/0.05^2-1)
=2/sqrt3*500*ln1-310+310*0.05^2/(0.1^2-0.05^2)*(0.1^2/0.05^2-1)
=2/sqrt3*500*ln1-310+310*0.05^2/0.0075*(0.1^2/0.05^2-1)
=2/sqrt3*500*ln1-310+310*0.05^2/0.0075*3
=2/1.732051*500*ln1-310+310*0.05^2/0.0075*3
=2/1.732051*500*0-310+310*0.05^2/0.0075*3
=2/1.732051*500*0-310+310*0.0025/0.0075*3
=1.1547*500*0-310+310*0.0025/0.0075*3
=577.35*0-310+310*0.0025/0.0075*3
=0-310+310*0.0025/0.0075*3
=0-310+0.775/0.0075*3
=0-310+103.333333*3
=0-310+309.999999
=-310+309.999999
=-0.000001 答案:2/sqrt(3)*500*ln1-310+310*0.05^2/(0.1^2-0.05^2)*(0.1^2/0.05^2-1)=-0.000001你的问题在这里没有得到解决?请到 热门难题 里面看看吧!