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It supports mathematical functions (including trigonometric functions).
Current location：Mathematical operation > History of Mathematical Computation > Answer
Overview: 1 questions will be solved this time.Among them
☆1 arithmetic calculations
[1/1 Formula]
Work: Calculate the value of equation 2/sqrt(3)*500*ln1-310+310*0.05^2/(0.1^2-0.05^2)*(0.1^2/0.05^2-1) .
Question type: Mathematical calculation
Solution:
2/sqrt(3)*500*ln1-310+310*0.05^2/(0.1^2-0.05^2)*(0.1^2/0.05^2-1)
=2/sqrt3*500*ln1-310+310*0.05^2/(0.1^2-0.05^2)*(0.1^2/0.05^2-1)
=2/sqrt3*500*ln1-310+310*0.05^2/0.0075*(0.1^2/0.05^2-1)
=2/sqrt3*500*ln1-310+310*0.05^2/0.0075*3
=2/1.732051*500*ln1-310+310*0.05^2/0.0075*3
=2/1.732051*500*0-310+310*0.05^2/0.0075*3
=2/1.732051*500*0-310+310*0.0025/0.0075*3
=1.1547*500*0-310+310*0.0025/0.0075*3
=577.35*0-310+310*0.0025/0.0075*3
=0-310+310*0.0025/0.0075*3
=0-310+0.775/0.0075*3
=0-310+103.333333*3
=0-310+309.999999
=-310+309.999999
=-0.000001
Answer:2/sqrt(3)*500*ln1-310+310*0.05^2/(0.1^2-0.05^2)*(0.1^2/0.05^2-1)=-0.000001