本次共计算 1 个题目：每一题对 x 求 1 阶导数。
    注意，变量是区分大小写的。
\[ \begin{equation}\begin{split}【1/1】求函数\frac{ax}{({({x}^{2} + {b}^{2})}^{(\frac{(m + 1)}{2})})} 关于 x 的 1 阶导数：\\\end{split}\end{equation} \]\[ \begin{equation}\begin{split}\\解:&\\ &原函数 = ax(x^{2} + b^{2})^{(\frac{-1}{2}m - \frac{1}{2})}\\&\color{blue}{函数的第 1 阶导数：}\\&\frac{d\left( ax(x^{2} + b^{2})^{(\frac{-1}{2}m - \frac{1}{2})}\right)}{dx}\\=&a(x^{2} + b^{2})^{(\frac{-1}{2}m - \frac{1}{2})} + ax((x^{2} + b^{2})^{(\frac{-1}{2}m - \frac{1}{2})}((0 + 0)ln(x^{2} + b^{2}) + \frac{(\frac{-1}{2}m - \frac{1}{2})(2x + 0)}{(x^{2} + b^{2})}))\\=&a(x^{2} + b^{2})^{(\frac{-1}{2}m - \frac{1}{2})} - \frac{amx^{2}(x^{2} + b^{2})^{(\frac{-1}{2}m - \frac{1}{2})}}{(x^{2} + b^{2})} - \frac{ax^{2}(x^{2} + b^{2})^{(\frac{-1}{2}m - \frac{1}{2})}}{(x^{2} + b^{2})}\\ \end{split}\end{equation} \]

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