There are 1 questions in this calculation: for each question, the 1 derivative of x is calculated.
    Note that variables are case sensitive.
\[ \begin{equation}\begin{split}[1/1]Find\ the\ first\ derivative\ of\ function\ {sh(8{cth(2cos(log*3x))}^{3})}^{5}\ with\ respect\ to\ x：\\\end{split}\end{equation} \]\[ \begin{equation}\begin{split}\\Solution:&\\ &Primitive\ function\ = sh^{5}(8cth^{3}(2cos(3logx)))\\&\color{blue}{The\ first\ derivative\ function：}\\&\frac{d\left( sh^{5}(8cth^{3}(2cos(3logx)))\right)}{dx}\\=&5sh^{4}(8cth^{3}(2cos(3logx)))ch(8cth^{3}(2cos(3logx)))*8*3cth^{2}(2cos(3logx))(1 - cth^{2}(2cos(3logx)))*2*-sin(3logx)*3log\\=&-720logsin(3logx)sh^{4}(8cth^{3}(2cos(3logx)))ch(8cth^{3}(2cos(3logx)))cth^{2}(2cos(3logx)) + 720logsin(3logx)sh^{4}(8cth^{3}(2cos(3logx)))ch(8cth^{3}(2cos(3logx)))cth^{4}(2cos(3logx))\\ \end{split}\end{equation} \]

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