There are 1 questions in this calculation: for each question, the 1 derivative of x is calculated.
    Note that variables are case sensitive.
\[ \begin{equation}\begin{split}[1/1]Find\ the\ first\ derivative\ of\ function\ 4{x}^{2} + \frac{1}{(2cos(\frac{pi}{(2x)}))}\ with\ respect\ to\ x：\\\end{split}\end{equation} \]\[ \begin{equation}\begin{split}\\Solution:&\\ &Primitive\ function\ = 4x^{2} + \frac{\frac{1}{2}}{cos(\frac{\frac{1}{2}pi}{x})}\\&\color{blue}{The\ first\ derivative\ function：}\\&\frac{d\left( 4x^{2} + \frac{\frac{1}{2}}{cos(\frac{\frac{1}{2}pi}{x})}\right)}{dx}\\=&4*2x + \frac{\frac{1}{2}sin(\frac{\frac{1}{2}pi}{x})*\frac{1}{2}pi*-1}{cos^{2}(\frac{\frac{1}{2}pi}{x})x^{2}}\\=&8x - \frac{pisin(\frac{\frac{1}{2}pi}{x})}{4x^{2}cos^{2}(\frac{\frac{1}{2}pi}{x})}\\ \end{split}\end{equation} \]

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