Mathematics
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current location:Derivative function > Derivative function calculation history > Answer
    There are 1 questions in this calculation: for each question, the 1 derivative of x is calculated.
    Note that variables are case sensitive.
\[ \begin{equation}\begin{split}[1/1]Find\ the\ first\ derivative\ of\ function\ \frac{(-2{x}^{2} + 100x + 30000)}{(20000 - 100x)}\ with\ respect\ to\ x:\\\end{split}\end{equation} \]\[ \begin{equation}\begin{split}\\Solution:&\\ &Primitive\ function\ = \frac{-2x^{2}}{(-100x + 20000)} + \frac{100x}{(-100x + 20000)} + \frac{30000}{(-100x + 20000)}\\&\color{blue}{The\ first\ derivative\ function:}\\&\frac{d\left( \frac{-2x^{2}}{(-100x + 20000)} + \frac{100x}{(-100x + 20000)} + \frac{30000}{(-100x + 20000)}\right)}{dx}\\=&-2(\frac{-(-100 + 0)}{(-100x + 20000)^{2}})x^{2} - \frac{2*2x}{(-100x + 20000)} + 100(\frac{-(-100 + 0)}{(-100x + 20000)^{2}})x + \frac{100}{(-100x + 20000)} + 30000(\frac{-(-100 + 0)}{(-100x + 20000)^{2}})\\=&\frac{-200x^{2}}{(-100x + 20000)^{2}} - \frac{4x}{(-100x + 20000)} + \frac{10000x}{(-100x + 20000)^{2}} + \frac{3000000}{(-100x + 20000)^{2}} + \frac{100}{(-100x + 20000)}\\ \end{split}\end{equation} \]





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