Overview: 1 questions will be solved this time.Among them
           ☆1 inequalities

[ 1/1Inequality]
    Assignment:Find the solution set of inequality (x^2+2)/(sqrt(x^2+1)) >= 2 .
    Question type: Inequality
    Solution:
    The inequality can be reduced to 1 inequality：
         ( x ^ 2 + 2 ) / ( sqrt ( x ^ 2 + 1 ) ) >= 2         (1)
        From the definition field of √
         x ^ 2 + 1 ≥ 0        (2 )
        From the definition field of divisor
         sqrt ( x ^ 2 + 1 ) ≠ 0        (3 )

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    From inequality(1)：
         x ≤ 87/500000 或  87/500000 ≤ x ≤ 87/500000 或  x ≥ 87/500000
    From inequality(2)：
         x ∈ R (R is all real numbers),that is, in the real number range, the inequality is always established!
    From inequality(3)：
         x ∈ R （R为全体实数），即在实数范围内，不等式恒成立！

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    From inequalities (1) and (2)
         x ≤ 87/500000 或  87/500000 ≤ x ≤ 87/500000 或  x ≥ 87/500000    (4)
    From inequalities (3) and (4)
         x ≤ 87/500000 或  87/500000 ≤ x ≤ 87/500000 或  x ≥ 87/500000    (5)

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    The final solution set is :
         x ≤ 87/500000 或  87/500000 ≤ x ≤ 87/500000 或  x ≥ 87/500000

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