Overview: 1 questions will be solved this time.Among them
           ☆1 inequalities

[ 1/1Inequality]
    Assignment:Find the solution set of inequality 1/x+√tan(asinx-2)-lg(ex-(x+e)^0) ) <10000 .
    Question type: Inequality
    Solution:
    The inequality can be reduced to 1 inequality：
        1 / x + √ tan ( arcsin x - 2 ) - lg ( e x - ( x + e ^ 0 ) ) <10000         (1)
        From the definition field of divisor
        x ≠ 0        (2 )
        From the definition field of arcsin
        x ≥ -1        (3 )
        x ≤ 1        (4 )
        From the definition field of lg
         e x - ( x + e ^ 0 ) > 0        (5 )

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    From inequality(1)：
         x ∈ R (R is all real numbers),that is, in the real number range, the inequality is always established!
    From inequality(2)：
         x < 0 或  x ＞ 0
    From inequality(3)：
         x ≥ -1
    From inequality(4)：
         x ≤ 1
    From inequality(5)：
         x < 0 或  x ＞ 0

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    From inequalities (1) and (2)
         x < 0 或  x ＞ 0    (6)
    From inequalities (3) and (6)
         -1 ≤ x < 0 或  x ＞ 0    (7)
    From inequalities (4) and (7)
         -1 ≤ x < 0 或  0 < x ≤ 1     (8)
    From inequalities (5) and (8)
         -1 ≤ x < 0 或  0 < x < 0 或  0 < x ≤ 1     (9)

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    The final solution set is :
         -1 ≤ x < 0 或  0 < x < 0 或  0 < x ≤ 1

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