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current location:Mathematical operation > History of Inequality Computation > Answer
    Overview: 1 questions will be solved this time.Among them
           ☆1 inequalities

[ 1/1Inequality]
    Assignment:Find the solution set of inequality (2^(2*a)+2^(2*a-2)+2)/(2^(4*a-2)+2^(2*a-2)+2^(2*a)+1) >-2 .
    Question type: Inequality
    Solution:
    The inequality can be reduced to 1 inequality:
         ( 2 ^ ( 2 * a ) + 2 ^ ( 2 * a - 2 ) + 2 ) / ( 2 ^ ( 4 * a - 2 ) + 2 ^ ( 2 * a - 2 ) + 2 ^ ( 2 * a ) + 1 ) > -2         (1)
        From the definition field of divisor
         2 ^ ( 4 * x - 2 ) + 2 ^ ( 2 * x - 2 ) + 2 ^ ( 2 * x ) + 1 ≠ 0        (2 )

    From inequality(1):
         a ∈ R (R is all real numbers),that is, in the real number range, the inequality is always established!
    From inequality(2):
         a ∈ R (R为全体实数),即在实数范围内,不等式恒成立!

    From inequalities (1) and (2)
         a ∈ R (R is all real numbers),that is, in the real number range, the inequality is always established!    (3)

    The final solution set is :

         a ∈ R (R is all real numbers),that is, in the real number range, the inequality is always established!




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