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Assignment:Find the solution set of inequality sqrt(sqrt(10+a))+sqrt(sqrt(7-a)) = 3a ≥0 .
Question type: Inequality
Solution:
The inequality can be reduced to 1 inequality:
sqrt ( sqrt ( 10 + a ) ) + sqrt ( sqrt ( 7 - a ) ) 3 * a ≥0 (1)
From the definition field of √
10 + x ≥ 0 (2 )
From the definition field of √
sqrt ( 10 + x ) ≥ 0 (3 )
From the definition field of √
7 - x ≥ 0 (4 )
From the definition field of √
sqrt ( 7 - x ) ≥ 0 (5 )
From inequality(1):
a ≥ -10
From inequality(2):
a ≥ -10
From inequality(3):
a ≥ -10
From inequality(4):
a ≤ 7
From inequality(5):
a ∈ R (R is all real numbers),that is, in the real number range, the inequality is always established!
From inequalities (1) and (2)
a ≥ -10 (6)
From inequalities (3) and (6)
a ≥ -10 (7)
From inequalities (4) and (7)
-10 ≤ a ≤ 7 (8)
From inequalities (5) and (8)
-10 ≤ a ≤ 7 (9)
The final solution set is :
-10 ≤ a ≤ 7Your problem has not been solved here? Please take a look at the hot problems !