Overview: 1 questions will be solved this time.Among them
           ☆1 inequalities

[ 1/1Inequality]
    Assignment:Find the solution set of inequality (-2000+500/(1+x)+700/(1+x)^2+2000/(1+x)^3) >= 0 .
    Question type: Inequality
    Solution:
    The inequality can be reduced to 1 inequality：
         ( -2000 + 500 / ( 1 + x ) + 700 / ( 1 + x ) ^ 2 + 2000 / ( 1 + x ) ^ 3 ) >= 0         (1)
        From the definition field of divisor
         1 + x ≠ 0        (2 )
        From the definition field of divisor
         1 + x ≠ 0        (3 )
        From the definition field of divisor
         1 + x ≠ 0        (4 )

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    From inequality(1)：
         -1.0001 ≤ x ≤ 0.2152
    From inequality(2)：
         x < -1 或  x ＞ -1
    From inequality(3)：
         x < -1 或  x ＞ -1
    From inequality(4)：
         x < -1 或  x ＞ -1

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    From inequalities (1) and (2)
         -1.0001 ≤ x < -1 或  -1 < x ≤ 0.2152     (5)
    From inequalities (3) and (5)
         -1.0001 ≤ x < -1 或  -1 < x ≤ 0.2152     (6)
    From inequalities (4) and (6)
         -1.0001 ≤ x < -1 或  -1 < x ≤ 0.2152     (7)

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    The final solution set is :
         -1.0001 ≤ x < -1 或  -1 < x ≤ 0.2152

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