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current location:Mathematical operation > History of Inequality Computation > Answer
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           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation (4500×12×0.9-60%×70X×6.95%)÷(40%×70X+5%×70X) = 3.8% .
    Question type: Equation
    Solution:Original question:
     (4500 × 12 ×
9
10
60
100
× 70 X ×
139
2000
) ÷ (
40
100
× 70 X +
5
100
× 70 X ) =
19
500
     Multiply both sides of the equation by:(
40
100
× 70 X +
5
100
× 70 X )
     (4500 × 12 ×
9
10
60
100
× 70 X ×
139
2000
) =
19
500
(
40
100
× 70 X +
5
100
× 70 X )
    Remove a bracket on the left of the equation::
     4500 × 12 ×
9
10
60
100
× 70 X ×
139
2000
=
19
500
(
40
100
× 70 X +
5
100
× 70 X )
    Remove a bracket on the right of the equation::
     4500 × 12 ×
9
10
60
100
× 70 X ×
139
2000
=
19
500
×
40
100
× 70 X +
19
500
×
5
100
× 70 X
    The equation is reduced to :
     48600
2919
1000
X =
133
125
X +
133
1000
X
    The equation is reduced to :
     48600
2919
1000
X =
1197
1000
X

    Transposition :
      -
2919
1000
X
1197
1000
X = - 48600

    Combine the items on the left of the equation:
      -
1029
250
X = - 48600

    By shifting the terms and changing the symbols on toth sides of the equation, we obtain :
     48600 =
1029
250
X

    If the left side of the equation is equal to the right side, then the right side must also be equal to the left side, that is :
     
1029
250
X = 48600

    The coefficient of the unknown number is reduced to 1 :
      X = 48600 ÷
1029
250
        = 48600 ×
250
1029
        = 16200 ×
250
343

    We obtained :
      X =
4050000
343
    This is the solution of the equation.

    Convert the result to decimal form :
      X = 11807.580175




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