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current location:Mathematical operation > History of Inequality Computation > Answer
    Overview: 1 questions will be solved this time.Among them
           ☆1 equations

[ 1/1 Equation]
    Work: Find the solution of equation a*145%*115%*140%*110%*300/(300+406-100)+a*289%*110%*300/(300+406-100) = 64720 .
    Question type: Equation
    Solution:Original question:
      a ×
145
100
×
115
100
×
140
100
×
110
100
× 300 ÷ (300 + 406100) + a ×
289
100
×
110
100
× 300 ÷ (300 + 406100) = 64720
     Multiply both sides of the equation by:(300 + 406100)
      a ×
145
100
×
115
100
×
140
100
×
110
100
× 300 + a ×
289
100
×
110
100
× 300 ÷ (300 + 406100) × (300 + 406100) = 64720(300 + 406100)
    Remove a bracket on the left of the equation::
      a ×
145
100
×
115
100
×
140
100
×
110
100
× 300 + a ×
289
100
×
110
100
× 300 ÷ (300 + 406100) × 300 = 64720(300 + 406100)
    Remove a bracket on the right of the equation::
      a ×
145
100
×
115
100
×
140
100
×
110
100
× 300 + a ×
289
100
×
110
100
× 300 ÷ (300 + 406100) × 300 = 64720 × 300 + 64720 × 40664720 × 100
    The equation is reduced to :
      a ×
154077
200
+ a × 286110 ÷ (300 + 406100) + a ×
1936011
5
÷ (300 + 406100) a × 95370 ÷ (300 + 406100) = 19416000 + 262763206472000
    The equation is reduced to :
     
154077
200
a + a × 286110 ÷ (300 + 406100) + a ×
1936011
5
÷ (300 + 406100) a × 95370 ÷ (300 + 406100) = 39220320
     Multiply both sides of the equation by:(300 + 406100)
     
154077
200
a (300 + 406100) + a × 286110 + a ×
1936011
5
÷ (300 + 406100) × (300 + 406100) a × 95370 ÷ (300 + 406100) = 39220320(300 + 406100)
    Remove a bracket on the left of the equation:
     
154077
200
a × 300 +
154077
200
a × 406
154077
200
a × 100 + a × 286110 + a = 39220320(300 + 406100)
    Remove a bracket on the right of the equation::
     
154077
200
a × 300 +
154077
200
a × 406
154077
200
a × 100 + a × 286110 + a = 39220320 × 300 + 39220320 × 40639220320 × 100

    
        a≈22748.483978 , keep 6 decimal places
    
    There are 1 solution(s).


解一元一次方程的详细方法请参阅:《一元一次方程的解法》




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