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〖1/1算式〗
作业:求算式 0.281*14.3*1000*0.785*(1-(sin(2*3.14159*0.281)/(2*3.14159*0.281)))+(3*0.281-1.25)*300*25445/1000 的值.
题型:数学计算
解:
0.281*14.3*1000*0.785*(1-(sin(2*3.14159*0.281)/(2*3.14159*0.281)))+(3*0.281-1.25)*300*25445/1000
=0.281*14.3*1000*0.785*(1-(sin1.765574/(2*3.14159*0.281)))+(3*0.281-1.25)*300*25445/1000
=0.281*14.3*1000*0.785*(1-(sin1.765574/1.765574))+(3*0.281-1.25)*300*25445/1000
=0.281*14.3*1000*0.785*(1-0.555678)+(3*0.281-1.25)*300*25445/1000
=0.281*14.3*1000*0.785*0.444322+(3*0.281-1.25)*300*25445/1000
=0.281*14.3*1000*0.785*0.444322+(-0.407)*300*25445/1000
=4.0183*1000*0.785*0.444322+(-0.407)*300*25445/1000
=4018.3*0.785*0.444322+(-0.407)*300*25445/1000
=3154.3655*0.444322+(-0.407)*300*25445/1000
=1401.553988+(-0.407)*300*25445/1000
=1401.553988+(-122.1)*25445/1000
=1401.553988+(-3106834.5)/1000
=1401.553988+(-3106.8345)
=-1705.280512 答案:0.281*14.3*1000*0.785*(1-(sin(2*3.14159*0.281)/(2*3.14159*0.281)))+(3*0.281-1.25)*300*25445/1000=-1705.280512 注:弧度制你的问题在这里没有得到解决?请到 热门难题 里面看看吧!