总述:本次共解1题。其中
☆算术计算1题
〖1/1算式〗
作业:求算式 1+1/(1300×((90+80+97.704)/4071.0×10^3+20)/(600-35))×((8000/700))^2×0.63 的值.
题型:数学计算
解:
1+1/(1300×((90+80+97.704)/4071.0×10^3+20)/(600-35))×((8000/700))^2×0.63
=1+1/(1300×(267.704/4071.0×10^3+20)/(600-35))×((8000/700))^2×0.63
=1+1/(1300×85.759/(600-35))×((8000/700))^2×0.63
=1+1/(1300×85.759/565)×((8000/700))^2×0.63
=1+1/197.321593×((8000/700))^2×0.63
=1+1/197.321593×(11.428571)^2×0.63
=1+1/197.321593×11.428571^2×0.63
=1+1/197.321593×130.612235102040984×0.63
=1+0.005068×130.612235102040984×0.63
=1+0.661943×0.63
=1+0.417024
=1.417024 答案:1+1/(1300×((90+80+97.704)/4071.0×10^3+20)/(600-35))×((8000/700))^2×0.63=1.417024你的问题在这里没有得到解决?请到 热门难题 里面看看吧!