总述:本次共解1题。其中
☆算术计算1题
〖1/1算式〗
作业:求算式 1+1/(1300×((90+80+87.18)/3632.5×10^3+20)/(600-35))×((8000/700))^2×0.71 的值.
题型:数学计算
解:
1+1/(1300×((90+80+87.18)/3632.5×10^3+20)/(600-35))×((8000/700))^2×0.71
=1+1/(1300×(257.18/3632.5×10^3+20)/(600-35))×((8000/700))^2×0.71
=1+1/(1300×90.8/(600-35))×((8000/700))^2×0.71
=1+1/(1300×90.8/565)×((8000/700))^2×0.71
=1+1/208.920354×((8000/700))^2×0.71
=1+1/208.920354×(11.428571)^2×0.71
=1+1/208.920354×11.428571^2×0.71
=1+1/208.920354×130.612235102040984×0.71
=1+0.004787×130.612235102040984×0.71
=1+0.625241×0.71
=1+0.443921
=1.443921 答案:1+1/(1300×((90+80+87.18)/3632.5×10^3+20)/(600-35))×((8000/700))^2×0.71=1.443921你的问题在这里没有得到解决?请到 热门难题 里面看看吧!