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☆算术计算1题
〖1/1算式〗
作业:求算式 286.561×(tan(45-16.13/2)*tan(45-16.13/2))-2×12.87×tan(45-16.13/2) 的值.
题型:数学计算
解:
286.561×(tan(45-16.13/2)*tan(45-16.13/2))-2×12.87×tan(45-16.13/2)
=286.561×(tan36.935*tan(45-16.13/2))-2×12.87×tan(45-16.13/2)
=286.561×(tan36.935*tan36.935)-2×12.87×tan(45-16.13/2)
=286.561×0.918356-2×12.87×tan(45-16.13/2)
=286.561×0.918356-2×12.87×tan36.935
=286.561×0.918356-2×12.87×-0.958309
=263.165014-2×12.87×(-0.958309)
=263.165014-25.74×(-0.958309)
=263.165014-(-24.666874)
=287.831888 答案:286.561×(tan(45-16.13/2)*tan(45-16.13/2))-2×12.87×tan(45-16.13/2)=287.831888 注:弧度制你的问题在这里没有得到解决?请到 热门难题 里面看看吧!