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☆算术计算1题
〖1/1算式〗
作业:求算式 286.561×(tan(45+16.13/2)*tan(45+16.13/2))+2×12.87×tan(45+16.13/2) 的值.
题型:数学计算
解:
286.561×(tan(45+16.13/2)*tan(45+16.13/2))+2×12.87×tan(45+16.13/2)
=286.561×(tan53.065*tan(45+16.13/2))+2×12.87×tan(45+16.13/2)
=286.561×(tan53.065*tan53.065)+2×12.87×tan(45+16.13/2)
=286.561×0.126788+2×12.87×tan(45+16.13/2)
=286.561×0.126788+2×12.87×tan53.065
=286.561×0.126788+2×12.87×-0.356073
=36.332496+2×12.87×(-0.356073)
=36.332496+25.74×(-0.356073)
=36.332496+(-9.165319)
=27.167177 答案:286.561×(tan(45+16.13/2)*tan(45+16.13/2))+2×12.87×tan(45+16.13/2)=27.167177 注:弧度制你的问题在这里没有得到解决?请到 热门难题 里面看看吧!