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           ☆算术计算1题

〖1/1算式〗
    作业：求算式 2*((0.5-0.124-0.065)*√(0.5-0.035)^2-(0.5-0.124-0.065)^2+π*(0.5-0.035)^2/180*arcsin((0.5-0.124-0.065)/(0.5-0.035))) 的值.
    题型：数学计算
    解:
          2*((0.5-0.124-0.065)*√(0.5-0.035)^2-(0.5-0.124-0.065)^2+π*(0.5-0.035)^2/180*arcsin((0.5-0.124-0.065)/(0.5-0.035)))
        =2*(0.311*√(0.5-0.035)^2-(0.5-0.124-0.065)^2+π*(0.5-0.035)^2/180*arcsin((0.5-0.124-0.065)/(0.5-0.035)))
        =2*(0.311*√0.465^2-(0.5-0.124-0.065)^2+π*(0.5-0.035)^2/180*arcsin((0.5-0.124-0.065)/(0.5-0.035)))
        =2*(0.311*√0.465^2-0.311^2+π*(0.5-0.035)^2/180*arcsin((0.5-0.124-0.065)/(0.5-0.035)))
        =2*(0.311*√0.465^2-0.311^2+π*0.465^2/180*arcsin((0.5-0.124-0.065)/(0.5-0.035)))
        =2*(0.311*√0.465^2-0.311^2+π*0.465^2/180*arcsin(0.311/(0.5-0.035)))
        =2*(0.311*√0.465^2-0.311^2+π*0.465^2/180*arcsin(0.311/0.465))
        =2*(0.311*√0.465^2-0.311^2+π*0.465^2/180*arcsin0.668817)
        =2*0.050659
        =0.101318
    答案:2*((0.5-0.124-0.065)*√(0.5-0.035)^2-(0.5-0.124-0.065)^2+π*(0.5-0.035)^2/180*arcsin((0.5-0.124-0.065)/(0.5-0.035)))=0.101318
    注：弧度制

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