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           ☆算术计算1题

〖1/1算式〗
    作业：求算式 2*((0.5-0.124-0.084)*√(0.5-0.047)^2-(0.5-0.124-0.084)^2+π*(0.5-0.047)^2/180*arcsin((0.5-0.124-0.084)/(0.5-0.047))) 的值.
    题型：数学计算
    解:
          2*((0.5-0.124-0.084)*√(0.5-0.047)^2-(0.5-0.124-0.084)^2+π*(0.5-0.047)^2/180*arcsin((0.5-0.124-0.084)/(0.5-0.047)))
        =2*(0.292*√(0.5-0.047)^2-(0.5-0.124-0.084)^2+π*(0.5-0.047)^2/180*arcsin((0.5-0.124-0.084)/(0.5-0.047)))
        =2*(0.292*√0.453^2-(0.5-0.124-0.084)^2+π*(0.5-0.047)^2/180*arcsin((0.5-0.124-0.084)/(0.5-0.047)))
        =2*(0.292*√0.453^2-0.292^2+π*(0.5-0.047)^2/180*arcsin((0.5-0.124-0.084)/(0.5-0.047)))
        =2*(0.292*√0.453^2-0.292^2+π*0.453^2/180*arcsin((0.5-0.124-0.084)/(0.5-0.047)))
        =2*(0.292*√0.453^2-0.292^2+π*0.453^2/180*arcsin(0.292/(0.5-0.047)))
        =2*(0.292*√0.453^2-0.292^2+π*0.453^2/180*arcsin(0.292/0.453))
        =2*(0.292*√0.453^2-0.292^2+π*0.453^2/180*arcsin0.644592)
        =2*0.049521
        =0.099042
    答案:2*((0.5-0.124-0.084)*√(0.5-0.047)^2-(0.5-0.124-0.084)^2+π*(0.5-0.047)^2/180*arcsin((0.5-0.124-0.084)/(0.5-0.047)))=0.099042
    注：弧度制

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