总述：本次共解1题。其中
           ☆算术计算1题

〖1/1算式〗
    作业：求算式 (1^2+2^2)/(1*2)+(2^2+3^2)/(2*3)+(3^2+4^2)/(3*4)+0.|+(2017^2+2018^2)/(2017*2018) 的值.
    题型：数学计算
    解:
          (1^2+2^2)/(1*2)+(2^2+3^2)/(2*3)+(3^2+4^2)/(3*4)+0.|+(2017^2+2018^2)/(2017*2018)
        =5/(1*2)+(2^2+3^2)/(2*3)+(3^2+4^2)/(3*4)+0.+(2017^2+2018^2)/(2017*2018)
        =5/2+(2^2+3^2)/(2*3)+(3^2+4^2)/(3*4)+0.+(2017^2+2018^2)/(2017*2018)
        =5/2+13/(2*3)+(3^2+4^2)/(3*4)+0.+(2017^2+2018^2)/(2017*2018)
        =5/2+13/6+(3^2+4^2)/(3*4)+0.+(2017^2+2018^2)/(2017*2018)
        =5/2+13/6+25/(3*4)+0.+(2017^2+2018^2)/(2017*2018)
        =5/2+13/6+25/12+0.+(2017^2+2018^2)/(2017*2018)
        =5/2+13/6+25/12+0.+8140613/(2017*2018)
        =5/2+13/6+25/12+0.+8140613/4070306
        =2.5+13/6+25/12+0+8140613/4070306
        =2.5+2.166667+25/12+0+8140613/4070306
        =2.5+2.166667+2.083333+0+8140613/4070306
        =2.5+2.166667+2.083333+0+2
        =4.666667+2.083333+0+2
        =6.75+0+2
        =6.75+2
        =8.75
    答案:(1^2+2^2)/(1*2)+(2^2+3^2)/(2*3)+(3^2+4^2)/(3*4)+0.|+(2017^2+2018^2)/(2017*2018)=8.75

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