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☆算术计算1题
〖1/1算式〗
作业:求算式 √(25×((1.330391*103.34*0.112)^2+1)÷(1.330391^2+1)÷1.330391^2÷(0.25*1.330391^2+1)÷((1.330391*103.34)^2+1)) 的值.
题型:数学计算
解:
√(25×((1.330391*103.34*0.112)^2+1)÷(1.330391^2+1)÷1.330391^2÷(0.25*1.330391^2+1)÷((1.330391*103.34)^2+1))
=√(25×(15.398052^2+1)÷(1.330391^2+1)÷1.330391^2÷(0.25*1.330391^2+1)÷((1.330391*103.34)^2+1))
=√(25×238.100005÷(1.330391^2+1)÷1.330391^2÷(0.25*1.330391^2+1)÷((1.330391*103.34)^2+1))
=√(25×238.100005÷2.76994÷1.330391^2÷(0.25*1.330391^2+1)÷((1.330391*103.34)^2+1))
=√(25×238.100005÷2.76994÷1.330391^2÷1.442485÷((1.330391*103.34)^2+1))
=√(25×238.100005÷2.76994÷1.330391^2÷1.442485÷(137.482606^2+1))
=√(25×238.100005÷2.76994÷1.330391^2÷1.442485÷18902.466953)
=√0.044529
=0.211019 答案:√(25×((1.330391*103.34*0.112)^2+1)÷(1.330391^2+1)÷1.330391^2÷(0.25*1.330391^2+1)÷((1.330391*103.34)^2+1))=0.211019你的问题在这里没有得到解决?请到 热门难题 里面看看吧!