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〖1/1算式〗
    作业：求算式 0.32*14.3*3.1416*0.4*0.4*(1-sin(2*180*0.32)/(2*3.1415926*0.32))+(3*0.32-1.25)*300*5.1 的值.
    题型：数学计算
    解:
          0.32*14.3*3.1416*0.4*0.4*(1-sin(2*180*0.32)/(2*3.1415926*0.32))+(3*0.32-1.25)*300*5.1
        =0.32*14.3*3.1416*0.4*0.4*(1-sin115.2/(2*3.1415926*0.32))+(3*0.32-1.25)*300*5.1
        =0.32*14.3*3.1416*0.4*0.4*(1-sin115.2/2.010619)+(3*0.32-1.25)*300*5.1
        =0.32*14.3*3.1416*0.4*0.4*0.571345+(3*0.32-1.25)*300*5.1
        =0.32*14.3*3.1416*0.4*0.4*0.571345+(-0.29)*300*5.1
        =4.576*3.1416*0.4*0.4*0.571345+(-0.29)*300*5.1
        =14.375962*0.4*0.4*0.571345+(-0.29)*300*5.1
        =5.750385*0.4*0.571345+(-0.29)*300*5.1
        =2.300154*0.571345+(-0.29)*300*5.1
        =1.314181+(-0.29)*300*5.1
        =1.314181+(-87)*5.1
        =1.314181+(-443.7)
        =-442.385819
    答案:0.32*14.3*3.1416*0.4*0.4*(1-sin(2*180*0.32)/(2*3.1415926*0.32))+(3*0.32-1.25)*300*5.1=-442.385819
    注：弧度制

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