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☆算术计算1题
〖1/1算式〗
作业:求算式 (11*sqrt(50^2*0.02^2+1))/(0.02*sqrt(0.02^2+1)*sqrt(1+1/16*0.02^2)*sqrt(1+2500^2*0.02^2)) 的值.
题型:数学计算
解:
(11*sqrt(50^2*0.02^2+1))/(0.02*sqrt(0.02^2+1)*sqrt(1+1/16*0.02^2)*sqrt(1+2500^2*0.02^2))
=(11*sqrt2)/(0.02*sqrt(0.02^2+1)*sqrt(1+1/16*0.02^2)*sqrt(1+2500^2*0.02^2))
=15.556354/(0.02*sqrt(0.02^2+1)*sqrt(1+1/16*0.02^2)*sqrt(1+2500^2*0.02^2))
=15.556354/(0.02*sqrt1.0004*sqrt(1+1/16*0.02^2)*sqrt(1+2500^2*0.02^2))
=15.556354/(0.02*sqrt1.0004*sqrt1.000025*sqrt(1+2500^2*0.02^2))
=15.556354/(0.02*sqrt1.0004*sqrt1.000025*sqrt2501)
=15.556354/1.0004
=15.550134 答案:(11*sqrt(50^2*0.02^2+1))/(0.02*sqrt(0.02^2+1)*sqrt(1+1/16*0.02^2)*sqrt(1+2500^2*0.02^2))=15.550134你的问题在这里没有得到解决?请到 热门难题 里面看看吧!