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〖1/1算式〗
作业:求算式 (0.153*2.53-3.1308+sqrt((3.1308-0.153*2.53)^2-0.2044*(0.31257-0.167*2.53)))/0.1022 的值.
题型:数学计算
解:
(0.153*2.53-3.1308+sqrt((3.1308-0.153*2.53)^2-0.2044*(0.31257-0.167*2.53)))/0.1022
=(0.153*2.53-3.1308+sqrt(2.74371^2-0.2044*(0.31257-0.167*2.53)))/0.1022
=(0.153*2.53-3.1308+sqrt(2.74371^2-0.2044*(-0.10994)))/0.1022
=(0.153*2.53-3.1308+sqrt7.550417)/0.1022
=0.004092/0.1022
=0.040039 答案:(0.153*2.53-3.1308+sqrt((3.1308-0.153*2.53)^2-0.2044*(0.31257-0.167*2.53)))/0.1022=0.040039你的问题在这里没有得到解决?请到 热门难题 里面看看吧!