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〖1/1算式〗
作业:求算式 0.153*2.53-3.1308+sqrt((3.1308-0.153*2.53)^2-0.2044*(0.31257-0.167*2.53)) 的值.
题型:数学计算
解:
0.153*2.53-3.1308+sqrt((3.1308-0.153*2.53)^2-0.2044*(0.31257-0.167*2.53))
=0.153*2.53-3.1308+sqrt(2.74371^2-0.2044*(0.31257-0.167*2.53))
=0.153*2.53-3.1308+sqrt(2.74371^2-0.2044*(-0.10994))
=0.153*2.53-3.1308+sqrt7.550417
=0.153*2.53-3.1308+2.747802
=0.38709-3.1308+2.747802
=-2.74371+2.747802
=0.004092 答案:0.153*2.53-3.1308+sqrt((3.1308-0.153*2.53)^2-0.2044*(0.31257-0.167*2.53))=0.004092你的问题在这里没有得到解决?请到 热门难题 里面看看吧!