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☆算术计算1题
〖1/1算式〗
作业:求算式 (0.78+2.243*(3^0.5))*(1-0.5)*(0.993+0.18*0.5)--1.06*0.25+1.71*(0.5^3) 的值.
题型:数学计算
解:
(0.78+2.243*(3^0.5))*(1-0.5)*(0.993+0.18*0.5)--1.06*0.25+1.71*(0.5^3)
=(0.78+2.243*1.732050807568877)*(1-0.5)*(0.993+0.18*0.5)--1.06*0.25+1.71*(0.5^3)
=4.66499*(1-0.5)*(0.993+0.18*0.5)--1.06*0.25+1.71*(0.5^3)
=4.66499*0.5*(0.993+0.18*0.5)--1.06*0.25+1.71*(0.5^3)
=4.66499*0.5*1.083--1.06*0.25+1.71*(0.5^3)
=4.66499*0.5*1.083--1.06*0.25+1.71*0.125
=2.332495*1.083-(-1.06)*0.25+1.71*0.125
=2.526092-(-1.06)*0.25+1.71*0.125
=2.526092-(-0.265)+1.71*0.125
=2.526092--0.265+0.21375
=2.791092+0.21375
=3.004842 答案:(0.78+2.243*(3^0.5))*(1-0.5)*(0.993+0.18*0.5)--1.06*0.25+1.71*(0.5^3)=3.004842你的问题在这里没有得到解决?请到 热门难题 里面看看吧!