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〖1/1算式〗
    作业：求算式 (((4-(1.88-3.2*(1/24-1/95))*cos(13))/3)*(1-24*tan(13)/π)*((1.88-3.2*(1/24-1/95))*cos(13)/(24*tan(13)/π)))^0.5 的值.
    题型：数学计算
    解:
          (((4-(1.88-3.2*(1/24-1/95))*cos(13))/3)*(1-24*tan(13)/π)*((1.88-3.2*(1/24-1/95))*cos(13)/(24*tan(13)/π)))^0.5
        =(((4-(1.88-3.2*0.031141)*cos(13))/3)*(1-24*tan(13)/π)*((1.88-3.2*(1/24-1/95))*cos(13)/(24*tan(13)/π)))^0.5
        =(((4-1.780349*cos(13))/3)*(1-24*tan(13)/π)*((1.88-3.2*(1/24-1/95))*cos(13)/(24*tan(13)/π)))^0.5
        =(((4-1.780349*cos13)/3)*(1-24*tan(13)/π)*((1.88-3.2*(1/24-1/95))*cos(13)/(24*tan(13)/π)))^0.5
        =((2.384428/3)*(1-24*tan(13)/π)*((1.88-3.2*(1/24-1/95))*cos(13)/(24*tan(13)/π)))^0.5
        =(0.794809*(1-24*tan(13)/π)*((1.88-3.2*(1/24-1/95))*cos(13)/(24*tan(13)/π)))^0.5
        =(0.794809*(1-24*tan13/π)*((1.88-3.2*(1/24-1/95))*cos(13)/(24*tan(13)/π)))^0.5
        =(0.794809*(-2.53722)*((1.88-3.2*(1/24-1/95))*cos(13)/(24*tan(13)/π)))^0.5
        =(0.794809*(-2.53722)*((1.88-3.2*0.031141)*cos(13)/(24*tan(13)/π)))^0.5
        =(0.794809*(-2.53722)*(1.780349*cos(13)/(24*tan(13)/π)))^0.5
        =(0.794809*(-2.53722)*(1.780349*cos13/(24*tan(13)/π)))^0.5
        =(0.794809*(-2.53722)*(1.780349*cos13/(24*tan13/π)))^0.5
        =(0.794809*(-2.53722)*(1.780349*cos13/3.53722))^0.5
        =(0.794809*(-2.53722)*0.456735)^0.5
        =-0.921054^0.5
        =-nan
    答案:(((4-(1.88-3.2*(1/24-1/95))*cos(13))/3)*(1-24*tan(13)/π)*((1.88-3.2*(1/24-1/95))*cos(13)/(24*tan(13)/π)))^0.5=-nan
    注：弧度制

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