总述：本次共解1题。其中
           ☆算术计算1题

〖1/1算式〗
    作业：求算式 √(((6×372987×(100-20))/(1.22×2×0.7×10×(290-2×10)^2))^2+(372987/(2×0.7×10×(290-2×10)))^2) 的值.
    题型：数学计算
    解:
          √(((6×372987×(100-20))/(1.22×2×0.7×10×(290-2×10)^2))^2+(372987/(2×0.7×10×(290-2×10)))^2)
        =√(((6×372987×80)/(1.22×2×0.7×10×(290-2×10)^2))^2+(372987/(2×0.7×10×(290-2×10)))^2)
        =√((179033760/(1.22×2×0.7×10×(290-2×10)^2))^2+(372987/(2×0.7×10×(290-2×10)))^2)
        =√((179033760/(1.22×2×0.7×10×270^2))^2+(372987/(2×0.7×10×(290-2×10)))^2)
        =√((179033760/1245132)^2+(372987/(2×0.7×10×(290-2×10)))^2)
        =√(143.786972^2+(372987/(2×0.7×10×(290-2×10)))^2)
        =√(143.786972^2+(372987/(2×0.7×10×270))^2)
        =√(143.786972^2+(372987/3780)^2)
        =√(143.786972^2+98.67381^2)
        =√30411.214097
        =174.388113
    答案:√(((6×372987×(100-20))/(1.22×2×0.7×10×(290-2×10)^2))^2+(372987/(2×0.7×10×(290-2×10)))^2)=174.388113

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