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〖1/1算式〗
    作业：求算式 (3.25*e^(-0.023590))*1+(3.25*e^(-2*0.023590))*2+(103.25*e^(-3*0.023590))*3 的值.
    题型：数学计算
    解:
          (3.25*e^(-0.023590))*1+(3.25*e^(-2*0.023590))*2+(103.25*e^(-3*0.023590))*3
        =(3.25*e^(-0.02359))*1+(3.25*e^(-2*0.023590))*2+(103.25*e^(-3*0.023590))*3
        =3.17423*1+(3.25*e^(-2*0.023590))*2+(103.25*e^(-3*0.023590))*3
        =3.17423*1+(3.25*e^(-0.04718))*2+(103.25*e^(-3*0.023590))*3
        =3.17423*1+3.100226*2+(103.25*e^(-3*0.023590))*3
        =3.17423*1+3.100226*2+(103.25*e^(-0.07077))*3
        =3.17423*1+3.100226*2+96.195562*3
        =3.17423+3.100226*2+96.195562*3
        =3.17423+6.200452+96.195562*3
        =3.17423+6.200452+288.586686
        =9.374682+288.586686
        =297.961368
    答案:(3.25*e^(-0.023590))*1+(3.25*e^(-2*0.023590))*2+(103.25*e^(-3*0.023590))*3=297.961368

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