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☆算术计算1题
〖1/1算式〗
作业:求算式 (3.25*e^(-0.02302))*1+(3.25*e^(-2*0.02302))*2+(103.25*e^(-3*0.02302))*3 的值.
题型:数学计算
解:
(3.25*e^(-0.02302))*1+(3.25*e^(-2*0.02302))*2+(103.25*e^(-3*0.02302))*3
=(3.25*e^(-0.02302))*1+(3.25*e^(-2*0.02302))*2+(103.25*e^(-3*0.02302))*3
=3.17604*1+(3.25*e^(-2*0.02302))*2+(103.25*e^(-3*0.02302))*3
=3.17604*1+(3.25*e^(-0.04604))*2+(103.25*e^(-3*0.02302))*3
=3.17604*1+3.103762*2+(103.25*e^(-3*0.02302))*3
=3.17604*1+3.103762*2+(103.25*e^(-0.06906))*3
=3.17604*1+3.103762*2+96.360198*3
=3.17604+3.103762*2+96.360198*3
=3.17604+6.207524+96.360198*3
=3.17604+6.207524+289.080594
=9.383564+289.080594
=298.464158 答案:(3.25*e^(-0.02302))*1+(3.25*e^(-2*0.02302))*2+(103.25*e^(-3*0.02302))*3=298.464158你的问题在这里没有得到解决?请到 热门难题 里面看看吧!