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☆算术计算1题
〖1/1算式〗
作业:求算式 102.75/(1+12%)+118.47/(1+12%)^2+((136.77)/(0.12-0.05)/(1+12%)^2) 的值.
题型:数学计算
解:
102.75/(1+12%)+118.47/(1+12%)^2+((136.77)/(0.12-0.05)/(1+12%)^2)
=102.75/1.12+118.47/(1+12%)^2+((136.77)/(0.12-0.05)/(1+12%)^2)
=102.75/1.12+118.47/1.12^2+((136.77)/(0.12-0.05)/(1+12%)^2)
=102.75/1.12+118.47/1.12^2+(136.77/(0.12-0.05)/(1+12%)^2)
=102.75/1.12+118.47/1.12^2+(136.77/0.07/(1+12%)^2)
=102.75/1.12+118.47/1.12^2+(136.77/0.07/1.12^2)
=102.75/1.12+118.47/1.12^2+1557.602952
=102.75/1.12+118.47/1.2544+1557.602952
=91.741071+118.47/1.2544+1557.602952
=91.741071+94.443559+1557.602952
=186.18463+1557.602952
=1743.787582 答案:102.75/(1+12%)+118.47/(1+12%)^2+((136.77)/(0.12-0.05)/(1+12%)^2)=1743.787582你的问题在这里没有得到解决?请到 热门难题 里面看看吧!