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〖1/1算式〗
作业:求算式 1.8421*4320/(247.29)^2*10200*450/1431111.11*(1+(247.29*18/4.4/450)^2) 的值.
题型:数学计算
解:
1.8421*4320/(247.29)^2*10200*450/1431111.11*(1+(247.29*18/4.4/450)^2)
=1.8421*4320/247.29^2*10200*450/1431111.11*(1+(247.29*18/4.4/450)^2)
=1.8421*4320/247.29^2*10200*450/1431111.11*(1+2.248091^2)
=1.8421*4320/247.29^2*10200*450/1431111.11*6.053913
=1.8421*4320/61152.344099999994796*10200*450/1431111.11*6.053913
=7957.872/61152.344099999994796*10200*450/1431111.11*6.053913
=0.130132*10200*450/1431111.11*6.053913
=1327.3464*450/1431111.11*6.053913
=597305.88/1431111.11*6.053913
=0.417372*6.053913
=2.526734 答案:1.8421*4320/(247.29)^2*10200*450/1431111.11*(1+(247.29*18/4.4/450)^2)=2.526734你的问题在这里没有得到解决?请到 热门难题 里面看看吧!