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☆算术计算1题
〖1/1算式〗
作业:求算式 200000*(4.75%/12)*(1+(4.75%/12))^36/(1+(4.75%/12))^35 的值.
题型:数学计算
解:
200000*(4.75%/12)*(1+(4.75%/12))^36/(1+(4.75%/12))^35
=200000*0.003958*(1+(4.75%/12))^36/(1+(4.75%/12))^35
=200000*0.003958*(1+0.003958)^36/(1+(4.75%/12))^35
=200000*0.003958*1.003958^36/(1+(4.75%/12))^35
=200000*0.003958*1.003958^36/(1+0.003958)^35
=200000*0.003958*1.003958^36/1.003958^35
=200000*0.003958*1.15281497774083/1.003958^35
=200000*0.003958*1.15281497774083/1.148270124587712
=791.6*1.15281497774083/1.148270124587712
=912.568336/1.148270124587712
=794.733152 答案:200000*(4.75%/12)*(1+(4.75%/12))^36/(1+(4.75%/12))^35=794.733152你的问题在这里没有得到解决?请到 热门难题 里面看看吧!