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〖1/1算式〗
作业:求算式 9*(7.61+2*0.3+1.28)*2.47+(48+3)*(2.25+2*0.3+1.785)*2.47+2*3*(7.61+1-0.083)*0.888 的值.
题型:数学计算
解:
9*(7.61+2*0.3+1.28)*2.47+(48+3)*(2.25+2*0.3+1.785)*2.47+2*3*(7.61+1-0.083)*0.888
=9*9.49*2.47+(48+3)*(2.25+2*0.3+1.785)*2.47+2*3*(7.61+1-0.083)*0.888
=9*9.49*2.47+51*(2.25+2*0.3+1.785)*2.47+2*3*(7.61+1-0.083)*0.888
=9*9.49*2.47+51*4.635*2.47+2*3*(7.61+1-0.083)*0.888
=9*9.49*2.47+51*4.635*2.47+2*3*8.527*0.888
=85.41*2.47+51*4.635*2.47+2*3*8.527*0.888
=210.9627+51*4.635*2.47+2*3*8.527*0.888
=210.9627+236.385*2.47+2*3*8.527*0.888
=210.9627+583.87095+2*3*8.527*0.888
=210.9627+583.87095+6*8.527*0.888
=210.9627+583.87095+51.162*0.888
=210.9627+583.87095+45.431856
=794.83365+45.431856
=840.265506 答案:9*(7.61+2*0.3+1.28)*2.47+(48+3)*(2.25+2*0.3+1.785)*2.47+2*3*(7.61+1-0.083)*0.888=840.265506你的问题在这里没有得到解决?请到 热门难题 里面看看吧!