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〖1/1算式〗
    作业：求算式 (20000000-1000)/12+((20000000*(1+0.01)^12-20000000))/12+(20000000*0.03)/12+(20000000*0.1)/12 的值.
    题型：数学计算
    解:
          (20000000-1000)/12+((20000000*(1+0.01)^12-20000000))/12+(20000000*0.03)/12+(20000000*0.1)/12
        =19999000/12+((20000000*(1+0.01)^12-20000000))/12+(20000000*0.03)/12+(20000000*0.1)/12
        =19999000/12+((20000000*1.01^12-20000000))/12+(20000000*0.03)/12+(20000000*0.1)/12
        =19999000/12+(2536500.602639)/12+(20000000*0.03)/12+(20000000*0.1)/12
        =19999000/12+2536500.602639/12+(20000000*0.03)/12+(20000000*0.1)/12
        =19999000/12+2536500.602639/12+600000/12+(20000000*0.1)/12
        =19999000/12+2536500.602639/12+600000/12+2000000/12
        =1666583.333333+2536500.602639/12+600000/12+2000000/12
        =1666583.333333+211375.05022+600000/12+2000000/12
        =1666583.333333+211375.05022+50000+2000000/12
        =1666583.333333+211375.05022+50000+166666.666667
        =1877958.383553+50000+166666.666667
        =1927958.383553+166666.666667
        =2094625.05022
    答案:(20000000-1000)/12+((20000000*(1+0.01)^12-20000000))/12+(20000000*0.03)/12+(20000000*0.1)/12=2094625.05022

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