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〖1/1算式〗
    作业：求算式 sqrt((-0.01575-0.0203875)^2+(0.0177-0.0203875)^2+(0.0585-0.0203875)^2+(0.0211-0.0203875)^2) 的值.
    题型：数学计算
    解:
          sqrt((-0.01575-0.0203875)^2+(0.0177-0.0203875)^2+(0.0585-0.0203875)^2+(0.0211-0.0203875)^2)
        =sqrt((-0.036138)^2+(0.0177-0.0203875)^2+(0.0585-0.0203875)^2+(0.0211-0.0203875)^2)
        =sqrt(-0.036138^2+(-0.002687)^2+(0.0585-0.0203875)^2+(0.0211-0.0203875)^2)
        =sqrt(-0.036138^2+(-0.002687)^2+0.038113^2+(0.0211-0.0203875)^2)
        =sqrt(-0.036138^2+(-0.002687)^2+0.038113^2+0.000713^2)
        =sqrt0.002767
        =0.052602
    答案:sqrt((-0.01575-0.0203875)^2+(0.0177-0.0203875)^2+(0.0585-0.0203875)^2+(0.0211-0.0203875)^2)=0.052602

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