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☆算术计算1题
〖1/1算式〗
作业:求算式 1-((1-0.02)^(11-1))*(0.02^(1-1))-((1-0.02)^(11-2))*(0.02^(2-1)) 的值.
题型:数学计算
解:
1-((1-0.02)^(11-1))*(0.02^(1-1))-((1-0.02)^(11-2))*(0.02^(2-1))
=1-(0.98^(11-1))*(0.02^(1-1))-((1-0.02)^(11-2))*(0.02^(2-1))
=1-(0.98^10)*(0.02^(1-1))-((1-0.02)^(11-2))*(0.02^(2-1))
=1-0.817072806887547*(0.02^(1-1))-((1-0.02)^(11-2))*(0.02^(2-1))
=1-0.817072806887547*(0.02^0)-((1-0.02)^(11-2))*(0.02^(2-1))
=1-0.817072806887547*1-((1-0.02)^(11-2))*(0.02^(2-1))
=1-0.817072806887547*1-(0.98^(11-2))*(0.02^(2-1))
=1-0.817072806887547*1-(0.98^9)*(0.02^(2-1))
=1-0.817072806887547*1-0.83374776213015*(0.02^(2-1))
=1-0.817072806887547*1-0.83374776213015*(0.02^1)
=1-0.817072806887547*1-0.83374776213015*0.02
=1-0.817073-0.83374776213015*0.02
=1-0.817073-0.016675
=0.182927-0.016675
=0.166252 答案:1-((1-0.02)^(11-1))*(0.02^(1-1))-((1-0.02)^(11-2))*(0.02^(2-1))=0.166252你的问题在这里没有得到解决?请到 热门难题 里面看看吧!