总述:本次共解1题。其中
☆算术计算1题
〖1/1算式〗
作业:求算式 abs((4/7)-(2/5))-abs((3/5)-(7/9))+abs((2/9)-(3/7)) 的值.
题型:数学计算
解:
abs((4/7)-(2/5))-abs((3/5)-(7/9))+abs((2/9)-(3/7))
=abs(0.571429-(2/5))-abs((3/5)-(7/9))+abs((2/9)-(3/7))
=abs(0.571429-0.4)-abs((3/5)-(7/9))+abs((2/9)-(3/7))
=abs0.171429-abs((3/5)-(7/9))+abs((2/9)-(3/7))
=abs0.171429-abs(0.6-(7/9))+abs((2/9)-(3/7))
=abs0.171429-abs(0.6-0.777778)+abs((2/9)-(3/7))
=abs0.171429-abs(-0.177778)+abs((2/9)-(3/7))
=abs0.171429-abs-0.177778+abs(0.222222-(3/7))
=abs0.171429-abs-0.177778+abs(0.222222-0.428571)
=abs0.171429-abs-0.177778+abs(-0.206349)
=0.171429-abs-0.177778+abs-0.206349
=0.171429-0.177778+abs-0.206349
=0.171429-0.177778+0.206349
=-0.006349+0.206349
=0.2 答案:abs((4/7)-(2/5))-abs((3/5)-(7/9))+abs((2/9)-(3/7))=0.2你的问题在这里没有得到解决?请到 热门难题 里面看看吧!