总述:本次共解1题。其中
☆算术计算1题
〖1/1算式〗
作业:求算式 4*(cos(2*π/7))^2+4*(cos(4*π/7))^2+4*(cos(8*π/7))^2 的值.
题型:数学计算
解:
4*(cos(2*π/7))^2+4*(cos(4*π/7))^2+4*(cos(8*π/7))^2
=4*(cos0.897598)^2+4*(cos(4*π/7))^2+4*(cos(8*π/7))^2
=4*0.62349^2+4*(cos(4*π/7))^2+4*(cos(8*π/7))^2
=4*0.62349^2+4*(cos1.795196)^2+4*(cos(8*π/7))^2
=4*0.62349^2+4*(-0.222521)^2+4*(cos(8*π/7))^2
=4*0.62349^2+4*(-0.222521)^2+4*(cos3.590392)^2
=4*0.62349^2+4*(-0.222521)^2+4*(-0.900969)^2
=4*0.3887397801+4*(-0.222521)^2+4*(-0.900969)^2
=4*0.3887397801+4*0.049515595441+4*(-0.900969)^2
=4*0.3887397801+4*0.049515595441+4*0.811745138961
=1.554959+4*0.049515595441+4*0.811745138961
=1.554959+0.198062+4*0.811745138961
=1.554959+0.198062+3.246981
=1.753021+3.246981
=5.000002 答案:4*(cos(2*π/7))^2+4*(cos(4*π/7))^2+4*(cos(8*π/7))^2=5.000002 注:弧度制你的问题在这里没有得到解决?请到 热门难题 里面看看吧!