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作业:求算式 0.0962/(1-2.345)+3.0609*0.2547/(3.0609-2.345)+0.1213*0.6491/(0.1213-2.345) 的值.
题型:数学计算
解:
0.0962/(1-2.345)+3.0609*0.2547/(3.0609-2.345)+0.1213*0.6491/(0.1213-2.345)
=0.0962/(-1.345)+3.0609*0.2547/(3.0609-2.345)+0.1213*0.6491/(0.1213-2.345)
=0.0962/(-1.345)+3.0609*0.2547/0.7159+0.1213*0.6491/(0.1213-2.345)
=0.0962/(-1.345)+3.0609*0.2547/0.7159+0.1213*0.6491/(-2.2237)
=-0.071524+3.0609*0.2547/0.7159+0.1213*0.6491/(-2.2237)
=-0.071524+0.779611/0.7159+0.1213*0.6491/(-2.2237)
=-0.071524+1.088994+0.1213*0.6491/(-2.2237)
=-0.071524+1.088994+0.078736/(-2.2237)
=-0.071524+1.088994+(-0.035408)
=1.01747+(-0.035408)
=0.982062 答案:0.0962/(1-2.345)+3.0609*0.2547/(3.0609-2.345)+0.1213*0.6491/(0.1213-2.345)=0.982062你的问题在这里没有得到解决?请到 热门难题 里面看看吧!