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〖1/1算式〗
作业:求算式 0.0962/(1-2.35)+3.0609*0.2547/(3.0609-2.35)+0.1213*0.6491/(0.1213-2.35) 的值.
题型:数学计算
解:
0.0962/(1-2.35)+3.0609*0.2547/(3.0609-2.35)+0.1213*0.6491/(0.1213-2.35)
=0.0962/(-1.35)+3.0609*0.2547/(3.0609-2.35)+0.1213*0.6491/(0.1213-2.35)
=0.0962/(-1.35)+3.0609*0.2547/0.7109+0.1213*0.6491/(0.1213-2.35)
=0.0962/(-1.35)+3.0609*0.2547/0.7109+0.1213*0.6491/(-2.2287)
=-0.071259+3.0609*0.2547/0.7109+0.1213*0.6491/(-2.2287)
=-0.071259+0.779611/0.7109+0.1213*0.6491/(-2.2287)
=-0.071259+1.096654+0.1213*0.6491/(-2.2287)
=-0.071259+1.096654+0.078736/(-2.2287)
=-0.071259+1.096654+(-0.035328)
=1.025395+(-0.035328)
=0.990067 答案:0.0962/(1-2.35)+3.0609*0.2547/(3.0609-2.35)+0.1213*0.6491/(0.1213-2.35)=0.990067你的问题在这里没有得到解决?请到 热门难题 里面看看吧!